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(^4-49)D=9
We move all terms to the left:
(^4-49)D-(9)=0
We multiply parentheses
D^2-49D-9=0
a = 1; b = -49; c = -9;
Δ = b2-4ac
Δ = -492-4·1·(-9)
Δ = 2437
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$D_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$D_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$D_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-\sqrt{2437}}{2*1}=\frac{49-\sqrt{2437}}{2} $$D_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+\sqrt{2437}}{2*1}=\frac{49+\sqrt{2437}}{2} $
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